3v^2-5v-1=0

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Solution for 3v^2-5v-1=0 equation: 



3v^2-5v-1=0

a = 3; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·3·(-1)
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{37}}{2*3}=\frac{5-\sqrt{37}}{6}
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{37}}{2*3}=\frac{5+\sqrt{37}}{6}
$

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